include<stdio.h>voidmain(){inta,b,c,d;scanf("%d",&a);b=a/100;c=(a%100)/10;d=a%10;printf("%d",100*d+10*c+b);}

可以通过取余运算符(%)和除号(/)来完成，具体的思路如下：比如要对123逆序输出。第一步是先对123除以10取余数，这样就会得到3；第二步是把123除以10取整，得到12，然后再把3*10+12%10，得到32；第三步是把12除以10...

voidmain(){intx,a,b,c;cin>>x;a=x/100;b=x/10%10;c=x%10;cout<<c*100+b*10+a<<endl;例如：include<stdio.h>intmain(){inta,b,c,t;scanf("%d",&a);b=a%10;c=(a-b)%100;t=a/1...

e=d*100+c*10+b;printf("逆序输出：%d",e);return0;}

C语言输入一个正整数n,将其逆序输出：include<stdio.h>include<stdlib.h>intmain(){inta;while(scanf("%d",&a)!=EOF){while(a>0){printf("%d",a%10);a=a/10;}printf("\n");}return0...

include<stdio.h>main(){intx,b0,b1,b2,s;printf("inputx:");scanf("%d",&x);b2=x/100;b1=(x-b2*100)/10;b0=x%10;s=b0*100+b1*10+b2;printf("s=%d\n",s);}运行结果：...

}publicstaticvoidmain(String[]args){intx=123023040;Stringrev=reverse(x);System.out.println(rev);System.out.println(reverse(123));}}输出结果：1、0403203212、321...

具体代码如下:include<stdio.h>voidreverse(intn){//当n不为零时继续while(n){//输出当前n的个位数字printf("%d",n%10);n/=10;}printf("\n");}intmain(){intn;scanf("%d",&n);//逆序nreverse...

"请输入一个整数：");scanf("%d",&di);printf("整数逆序：%d\n",reversei(di));printf("请输入一个整数：");scanf("%s",ds);reverses(ds,re);printf("字符串逆序：%s\n",re);retur

=n;}}voidmain(){charstr[80],*p=str;printf("请输入");scanf("%s",p);printf("你输入的字符串是:\n");printf("%s\n",p);invert(p);p=str;printf("逆序字符串\n");printf("%